0
1.3kviews
A body of mass 25 kg resting on a horizontal table is connected by string passing over a smooth pulley at the edge of the table to another body of mass 3.75 kg & hanging vertically as shown.

Initially friction between mass A & table is just sufficient to prevent the motion. If an additional 1.25 kg is added to the 3.75 kg mass, find the acceleration of the masses.

enter image description here

Mumbai University > FE > Sem 1 > Engineering Mechanics

Marks : 04

Years : DEC 2015

1 Answer
0
7views

enter image description here enter image description here

As initially system is in equilibrium, applying conditions of equilibrium.

Block A

$T - µ 25 g=0 \\ 3.75g - µ 25(9.81)=0 \\ µ=0.15 $

Block B

$3.75(g)-T=0 \\ T= 3.75g$

Now, after addition of mass to block B, system starts motion

Let acc of blocks be 'a'

Applying NSL to block A

$\sum Fx= max \\ T - 0.15(25g)=25a --------------(i) $

Applying NSL to block B

$\sum Fy= may \\ 5g - T=5a------(ii) $

Solving (i) & (ii)

$T=47 N$ & $a=0.409 m/s2 $

Acceleration of masses is 0.409 m/s2

Please log in to add an answer.