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Draw output waveform for following circuits.

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Mumbai University > Electronics Engineering > Sem 4 > Discrete Electronic Circuits

Marks: 5M

Year: Dec 2015

1 Answer
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Figure1: Circuit diagram

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Figure 2: Input Waveform

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Figure 3: Output Waveform

  1. Figure 1 shows Series Negative Clipper with Positive Bias Voltage Connected in Series, when Vin= 0 diode will be forward bias, till Vin reaches 1V output voltage will be 1V and when Vin > 1V then Vo = Vin +1 V as shown in Figure 2.
  2. During negative half cycle diode will be reverse biased hence output voltage will be zero.

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Figure 4: Circuit Diagram

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Figure 5: Input Waveform

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Figure 6: Output Waveform

  1. Figure 4 shows Positive Clamper with positive bias.
  2. During negative half cycle diode is forward biased which makes diode short circuit and capacitor starts charging. Hence voltage across capacitor becomes $V_C$= 5 + 2 = 7V and output voltage $V_O$ is 2V.
  3. During positive half cycle diode is reversed biased hence voltage at output terminal becomes $V_O = 5 + V_C$ = 5 + 7 = 12V.
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