written 5.5 years ago by |
(a) CE circuit
Voltage gain,
$A_{v}=\frac{h_{fe}(R_{C}||R_{L})}{h_{ie}}$
$\frac{100(5.6k\Omega||33k\Omega)}{1.5k\Omega}$=319.......(i)
Device input impedance
$Z_{0}=g_{ic}=1k\Omega$...........(ii)
Circuit input impedance
$Z_{i}=Z_{b}||R_{1}||R_{2}$
$1k\Omega||100k\Omega||47k\Omega$
=970$\Omega$ .........(iii)
Input voltage
$u_{i}\frac{v_{s}\times Z_{i}}{r_{s}+Z_{i}}$
=$\frac{50mV\times 970\Omega}{600\Omega+970\Omega}$=30.9mV ..........(iv)
Output voltage
$v_{0}=A_{v}\times v_{i}=319\times30.9mV$
=99.v ........(v)
(b)CB circuit
Voltage gain
$A_{v}=\frac{h_{fe}(R_{C}||R_{L})}{h_{ie}}=319$ ......(vi)
From Table 4.6 Device input impedance
$Z_{e}=\frac{h_{fe}}{1+h_{fe}}=\frac{1.5k\Omega}{1+100}$=14.85\Omega.....(vii)
Circuit input impedance,
Z_{i}=Z_{e}||R_{E}
=14.85\Omega||5.6k\Omega
14.81$\Omega$......(viii)
Input voltage
$v_{i}\frac{V_{s} \times Z_{i}}{r_{s}+Z_{i}}$
$\frac{50mV \times 14.81\Omega}{600\Omega+14.81\Omega}$=1.2mV....(ix)
Output voltage
$v_{o}=A_{v} \times v_{i}$
319 \times 1.2 mV=383 mV.....(x)