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Calculate the maximum bit rate for a channel having b.w. 3100 Hz and S/N ratio 20 dB
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written 5.5 years ago by
teamques10
★ 64k
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Given B = 3100 Hz
S/N = 20 dB
But 20 dB = 10 log (S/N)
∴ S/N = 100
The maximum bit rate: -
$R_{\max }=B \log_2 \big[1+\frac{S}{N}\big] \\ =3100 log_2[1+100 ] \\ =\frac{(3100 \log_{10}101 )}{log_{10}2 } =20,640 bits/sec$
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