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Show that in metal cutting $V_{c} = V \times r_{c}$
written 5.2 years ago by | • modified 2.2 years ago |
Mumbai University > Mechanical Engineering > Sem 4 > Production Process II
Marks: 5M
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written 5.2 years ago by | • modified 2.2 years ago |
Mumbai University > Mechanical Engineering > Sem 4 > Production Process II
Marks: 5M
written 5.2 years ago by |
Also $r_{c}=\frac{t_{2}}{t_{1}}=\frac{cos(\phi-\alpha)}{sin \theta}$
uisng $\frac{V_{c}}{Sin[90-(\phi-\alpha)]}=\frac{V_{f}}{Sin\phi}$
Therefore, $V_{c}=\frac{V_{f}}{Sin\phi}\times Sin[90-(\phi-\alpha)]$
Therefore $V_{c}=V_{f}\times r_{c}$ $ \ \ \ $ but $ \ \ \ $ $sin [90-(\theta-\alpha)=cos(\phi-\alpha)]$
Hence proved