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Locate the shear centre for thin walled channel section as shown in figure. Assume the uniform section as 10mm. Cross sectional dimension are in mm.
written 5.3 years ago by gravatar for ashishgoklani ashishgoklani • 180 modified 2.0 years ago by gravatar for Chandan15 Chandan15 • 300

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Subject: Structural Analysis 1

Topic: Shear Centre

Difficulty: High
structural analysis
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written 2.0 years ago by gravatar for Chandan15 Chandan15 • 300 •   modified 2.0 years ago

Using Relation, $e=\frac{b^{2} h^{2} t}{4 I_{A O S}}$ $I_{AOS}=\left(\frac{1 00 \times 300^3}{12}\right)-\left(\frac{90 \times 280^3}{12}\right).$ $I_{\text {AOS }}=60.36 \times 10^{6} \mathrm{~mm}^{4}$ $Shear Centre, e=\frac{95^{2} \times 290^{2} \times 10}{4 \times 60.36 \times 10^{6}}=31.436 \mathrm{~mm}$
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