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The requested tracks in the order received are 54, 57, 40, 20, 80, 120, 150, 45, 180. Apply the following disk scheduling algorithm starting track at 90.

a) FCFS

b) SSTF

c) C-SCAN

Marks: 10 M

Year: May 2015

1 Answer
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Total time travelled= $|90-54|+|54-57|+|57-40|+|40-20|+|20-80|+|80-120|+|120-150|+|150-45|+|45-180| =446$

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Total time take = $|90-80|+|80-57|+|57-54|+|54-45|+|45-40|+|40-20|+|20-120|+|120-150|+|150-180| =230$

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Total time take= $|90-120|+|120-150|+|150-180|+|180-200|+|200-0|+|0-20|+|20-40|+|40-45|+|45-54|+|54-57|+|57-80| =421$

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