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Calculate the percentage atom economy for the following reaction :

$CH_3 NH_2 + CO Cl_2 → CH_3 N=C=O + 2HCl$

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Molecular weight of $CH_3NH_2$ = 31

Molecular weight of $COCl_2$ = 98

Molecular weight of $CH_3N=C=O$ = 57

% Atom economy = Molecular weight of desired product/ Sum of the molecular weight of desired product $\times$ 100

= 57/31 +98 $\times$ 100

= 44.18%

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