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Environmental Engineering 2 Question Paper - Dec 18 - Civil Engineering (Semester 7) - Mumbai University (MU)
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Environmental Engineering 2 - Dec 18

Civil Engineering (Semester 6)

Total marks: 80
Total time: 3 Hours
INSTRUCTIONS
(1) Question No.1 is compulsory.
(2) Attempt any three questions from remaining five questions.
(3) Assume any suitable data where ever required.
(4) Figures to the right indicate full marks.

1(a) Explain oxygen Sag curve.
(5 marks) 1619

1(b) Give the difference between aerobic and anaerobic processes
(5 marks) 521

1(c) Draw a flow sheet for conventional sewage treatment plant?
(5 marks) 1620

1(d) Write short note on BOD?
(5 marks) 00

1(e) Prove that 50dB+50dB is not equal to 100dB.
(5 marks) 00

2(a) Design the dimension of a septic tank for a colony of 200 persons provided with an assured water supply from municipal head works at a rate of 100 litres per person per day. Assume any data if required?
(10 marks) 1115

2(b) Differentiate between primary & secondary pollutants. Write a short note on air pollution caused by automobiles & its control?
(10 marks) 1116

3(a) Calculate the discharge of 1m circular sewer laid at a slope of 1in500 when it’s running half full. Assume manning (N) as 0.011. Draw a fig of partially filled circular sewer section?
(10 marks) 514

3(b) Explain the process mechanism of ASP with neat sketch?
(10 marks) 00

4(a)The 5 day 30°C BOD of sewage sample is 110mg/lit. Calculate its 5 day 20°C BOD. Assume KD=0.10 per day?
(10 marks) 00

4(b) Explain two sewer appurtenances with neat sketch?
(10 marks) 00

5(a) Enlist different types of traps in plumbing. Explain any two with neat sketches?
(8 marks) 00

5(b) Determine the size of high rate trickling filter for following data:
i. Flow= 4.5 MLD

ii. BOD5 of raw sewage = 250mg/l

iii. Recirculation ratio = 1.4

iv. BOD removed in primary clarifier = 25%

v. Final effluent BOD desired = 50mg/l

(6 marks) 529

Q6) Write short note on (any four)

  • a) Sewage sickness

  • b) Crown corrosion 745

  • c) Combined & separate system of sewerage 745

  • d) Oxidation Pond 582

  • e) Population Equivalent 3068

(20 marks)

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