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Wireless Network Question Paper - Dec 17 - Electronics And Telecomm (Semester 8) - Mumbai University (MU)
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Wireless Network - Dec 17

Electronics And Telecomm (Semester 8)

Total marks: 80
Total time: 3 Hours
INSTRUCTIONS
(1) Question 1 is compulsory.
(2) Attempt any three from the remaining questions.
(3) Draw neat diagrams wherever necessary.
(4) Assume suitable data if required.

1.(a) Explain Softer and soft handoff in CDMA.
(5 marks) 9501

1.(b) Define open loop closed loop and outer loop power control.
(5 marks) 9485

1.(c) Explain concept of HSDPA w.r.t. WCDMA.
(5 marks) 9486

1.(d) What is the role of GPRS in GSM?
(5 marks) 9487

2.(a) What is localization in wireless sensor network? Explain with examples centralized and Distributed schemes in localization algorithms.
(10 marks) 6412

2.(b) Give the distributed radio access network overview. Explain in detail functions of node 3 and RNC also draw UTRAN logical architecture.
(10 marks) 9498

3.(a) What is UMTS? List important features &UMTS air interface.
(10 marks) 9503

3.(b) Explain middleware architecture.
(10 marks) 6427

4.(a) Draw and explain CDMA 2000 evolution path.
(10 marks) 9504

4.(b) Using traffic data per cell for a GSM/GPRS network, calculate ) (a) data Erlangs, (b) time slot (TS) utilization, and (c) TS capacity. ) Use the following data : ) - No of BTS: 40 ) - Subscriber usage per month: 150 minutes ) - Days per month: 24 ) - Busy hours per day: 6 ) - Allocated spectrum: 4.8 MHz ) - Frequency reuse plan: 4/12 ) - RF channel width: 200 kHz (full rate) ) - Present number of subscribers in a zone: 50,000 ) - Subscriber growth per year: 5% ) - Network roll-over period: 4 years ) - Number of packet calls per session (NPCS): 5 ) - Number of packets within a packet call (NPP): 25 ) - Reading time between packet calls (Tr): 120 s ) - Packet size (NBP): 480 bytes ) - Time interval between two packets inside a packet call (Tint): 0.01 s ) - Total packet service holding time during one hour (stot): 3000 s ) - Busy hour packet sessions per subscriber: 0.15 ) - Average call holding time during busy hour: 120 seconds ) - No. of transceivers (TX) per cell: 3 ) - No. of TSs per cell for signalling: 3 ) - Radio link control (RLC) efficiency: 80% ) - Total numbers of transmitted radio blocks: 9000 ) - TSs allocated for data traffic c per cell: 3 ) - Data throughput per cell: 15.5 kbps ) - Voice traffic per cell: 8.82 Erlangs)
(10 marks) 9505

5.(a) Describe the model of wireless sensor networks What are the factors influencing design of wireless sensor network.
(10 marks) 12107

5.(b) Explain back off algorithm why is CSMA-CD not used in WLAN.
(10 marks) 9506

6.(a) Write short note on the following : IEEE 802.16
(10 marks) 9551

6.(b) Write short note on the following : UWB technology
(10 marks) 6391

6.(c) Write short note on the following : ZigBee Technology
(10 marks) 12108

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