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Wireless Network Question Paper - May 18 - Electronics And Telecomm (Semester 8) - Mumbai University (MU)
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Wireless Network - May 18
Electronics And Telecomm (Semester 8)
Total marks: 80
Total time: 3 Hours
INSTRUCTIONS
(1) Question 1 is compulsory.
(2) Attempt any three from the remaining questions.
(3) Draw neat diagrams wherever necessary.
(4) Assume suitable data if required.
Q.1 Solve any four:
1.(a)
Explain E-UTRAN with suitable diagram.
(5 marks)
9507
1.(b)
What are the three phases of wireless network design?
(5 marks)
12109
1.(c)
Explain What is ‘hidden node' and 'exposed node' problem in WLAN?
(5 marks)
6408
1.(d)
What are the basic middleware functions for WSN? Explain.
(5 marks)
12114
1.(e)
With a suitable example explain category 1 and category 2 of sensor network.
(5 marks)
12115
2.(a)
Explain middleware architecture of WSN.
(10 marks)
6427
2.(b)
Explain HSDPA emphasizing its primary objectives and how it achieves performance improvement?
(10 marks)
9491
3.(a)
Give the detailed radio access network overview. Explain in detail functions of Node B and RNC also draw UTRAN logical architecture.
(10 marks)
9498
3.(b)
List out the factors affecting size of the cellular network and the frequency planning. Discuss these factors in detail.
(10 marks)
9508
4.(a)
Why TCP and UDP protocols are unsuitable for implementation in WSN.
(10 marks)
6410
4.(b)
Using the following data for a GSM network, estimate the voice and data traffic per subscriber. If there are 40 BTS sites, calculate voice and data traffic per cell.
Use the following data :
- Subscriber usage per month: 150 minutes
- Days per month: 24
- Busy hours per day: 6
- Allocated spectrum: 4.8 MHz
- Frequency reuse plan: 4/12
- RF channel width: 200 kHz (full rate)
- Present number of subscribers in a zone: 50,000
- Subscriber growth per year: 5%
- Network roll-over period: 4 years
- Number of packet calls per session (NPCS): 5
- Number of packets within a packet call (NPP): 25
- Reading time between packet calls (T$_{r}$): 120 s
- Packet size (NBP): 480 bytes
- Time interval between two packets inside a packet call (T$_{int}$): 0.01 s
- Total packet service holding time during one hour (T$_{tot}$): 3000 s
- Busy hour packet sessions per subscriber: 0.15
- Penetration of data subscribers: 25%
- Data rate of each subscriber: 48 kbps
- Packet transmission time: 10s
(10 marks)
9545
- Subscriber usage per month: 150 minutes
- Days per month: 24
- Busy hours per day: 6
- Allocated spectrum: 4.8 MHz
- Frequency reuse plan: 4/12
- RF channel width: 200 kHz (full rate)
- Present number of subscribers in a zone: 50,000
- Subscriber growth per year: 5%
- Network roll-over period: 4 years
- Number of packet calls per session (NPCS): 5
- Number of packets within a packet call (NPP): 25
- Reading time between packet calls (T$_{r}$): 120 s
- Packet size (NBP): 480 bytes
- Time interval between two packets inside a packet call (T$_{int}$): 0.01 s
- Total packet service holding time during one hour (T$_{tot}$): 3000 s
- Busy hour packet sessions per subscriber: 0.15
- Penetration of data subscribers: 25%
- Data rate of each subscriber: 48 kbps
- Packet transmission time: 10s
5.(a)
Why network management design is critical issue in WSN? Explain.
(10 marks)
6426
5.(b)
What is localization of WSN nodes? Explain with examples centralized and distributed schemes in localization.
(10 marks)
6412
6.(a)
Explain Bluetooth security features and security levels with proper diagram.
(10 marks)
6387
6.(b).1
Write short note on the following: WIMAX
(5 marks)
6400
6.(b).2
Write short note on the following: RFID
(5 marks)
9555
6.(b).3
Write short note on the following: ZigBee
(5 marks)
12108
6.(b).4
Write short note on the following: LTE
(5 marks)
9492
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