Page: Model Testing of centri fugal pump.
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Before manufacturing any large sized pumps, their model which are completely similar with actual pumps called as prototypes are made.

then tests are conducted on the models and performance of the prototypes are predicted.

there would be a complete similarity between a model and actual pump only if the following conditions exist.

1] specific speed of model = specific speed of prototype.

$(Ns)_m = (Ns)_p$

$(\frac{N \sqrt Q}{Hm^3/4})_m = \frac{N\sqrt Q}{Hm^3/4})_p$------(1)

2] Tangential velocity (u)

$u = \frac{\pi DN}{60} or u \alpha \sqrt H$

$\therefore$ $\sqrt{Hn} \alpha DN$

$\therefore$ $\frac{\sqrt{Hn}}{DN} = constant$

or $(\frac{\sqrt {Hm}}{DN})_m = (\frac{\sqrt {Hm}}{Hm}_p$

3] From equation $(Q \alpha D^2 \times vf)$

$\therefore$ $Q \alpha D^2 \times vf$

$\alpha D^2 \times D \times N$

$\alpha D^3 \times N$

$\therefore$ $\frac{Q}{D^3N} = constant$

or $(\sqrt {Q}{D^3N})_m = (\frac{Q}{D^3N})_p$

4] Power of the pump.

$p = \frac{p \times 9 \times Q \times Hm}{75}$

$p \alpha Q \alpha Hm$

$\alpha D^3 \times N \times Hm$

$\alpha D^3 N \times D^2 N^2$

$\alpha D^5 N^3$

$\therefore$ $\frac{p}{D^5 N^3} = constant$

or $(\frac{p}{D^5 N^3})_m = (\frac{p}{D^5 N^3})_p$

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written 6 days ago by gravatar for Renu Banswani Renu Banswani10
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