0
707views
Porter Governor :
1 Answer
0
0views

enter image description here

$h = \frac{g}{w^2} [ 1 + \frac{m}{2m} (1 + q)]$

$h = \frac{895}{N^2} [ 1 + \frac{M}{2m} (1 + q)]$

Where, $m =$ mass of each ball.

$M =$ mass of central load.

$q = \frac{tan \ \beta}{tan \ \alpha}$

NOTE: If all arms are equal in length and they intersect on the axis of spindle, then $\alpha = \beta$

$\therefore q = 1$

Please log in to add an answer.