0
707views
written 4.8 years ago by |
$h = \frac{g}{w^2} [ 1 + \frac{m}{2m} (1 + q)]$
$h = \frac{895}{N^2} [ 1 + \frac{M}{2m} (1 + q)]$
Where, $m =$ mass of each ball.
$M =$ mass of central load.
$q = \frac{tan \ \beta}{tan \ \alpha}$
NOTE: If all arms are equal in length and they intersect on the axis of spindle, then $\alpha = \beta$
$\therefore q = 1$