Solution:
Class |
$f_i$ |
$x_i$ |
$u_i$ |
$ui^2$ |
$fiui$ |
$fiui^2$ |
0-10 |
3 |
5 |
-2 |
4 |
-6 |
12 |
10-20 |
5 |
15 |
-1 |
1 |
5 |
5 |
20-30 |
8 |
25=A |
0 |
0 |
0 |
0 |
30-40 |
3 |
35 |
1 |
1 |
3 |
3 |
40-50 |
1 |
45 |
2 |
4 |
4 |
4 |
|
$\sum \mathrm{f}{\mathrm{i}}=$20 |
|
|
|
$\sum \mathrm{u}{\mathrm{i}} \mathrm{f}{\mathrm{i}}$= 6 |
$\sum \mathrm{u}{\mathrm{i}}^{2} \mathrm{f}{\mathrm{i}}$= 24 |
Mean:
$\overline{\mathrm{X}}=\mathrm{A}+\mathrm{h}\left(\frac{\sum \mathrm{u}{\mathrm{i}} \mathrm{f}{\mathrm{i}}}{\mathrm{N}}\right)$
$ =25+10\left(\frac{6}{20}\right)$
= 28
Variance:
$
\operatorname{Var}(X)=h^{2}\left[\frac{1}{N} \sum_{i=1}^{n} f_{i} u_{i}^{2}-\left(\frac{1}{N} \sum_{i=1}^{n} u_{i} f_{i}\right)^{2}\right]
$
$
=100\left[\frac{24}{20}-\frac{36}{400}\right]
$
$
=100[1.2 - 0.09]
$
$
=111
$
Standard Deviation:
$\sigma=\sqrt{111}$
= 10.53
The standard deviation is $10.53$