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Monochromatic high energy x-rays are incident on a crystal. If 1st order reflection is observed at an angle 3.4°, at what angle would 2nd order reflection be expected.
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written 2.9 years ago by
teamques10
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Given,
For first order reflection,
$Ø_1 = 3.4°$
To find,
$Ø_2 = ??$
Sice it is the same monochromatic x-ray, values of d(interstitial distance) and L(here lambda)
Using Bragg's Law, $2d\sin\phi = nL $
For first order reflection,
$2d\sin(3.4) = (1)L $......(1)
For second order reflection,
$2d\sinØ_2 = (2)L $ .......(2)
Dividing (1) and (2),
=> $\dfrac{\sin3.4}{\sinØ_2} = \dfrac{1}{2}$
=> $\sin Ø_2 = 2 \times \sin3.4$
=> Ø2 = 6.25°
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