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Perform histogram stretching so that the new image has a dynamic range of [0,7]
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written 7.8 years ago by
teamques10
★ 64k
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$Here, r_{min} = 0 \\ r_{max} = 3 \\ s_{min} = 0 \hspace{1cm} s_{max} = 7 \\ s = s_{max} - s_{min}/r_{max} – r_{min}(r –r_{min}) + s_{min} \\ Therefore,s = 7/3 (r-0)+0 \\ When,r=0 ,s=0 \\ r=1 ,s = 7/3 (1-0)=2.3 ≈ 2 \\ r=2 ,s = 7/3 (2-0) = 4.67 ≈ 5 \\ r=3 ,s = 7/3 (3-0) = 7$ \
Therefore,we have
| r=0 | S=0 |
|---|---|
| r=1 | S=2 |
| r=2 | S=5 |
| r=3 | S=7 |
INPUT HISTOGRAM
OUTPUT HISTOGRAM:
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