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Calculate ultimate L.C.C of short axially loaded R.C. column of size $400 \times 400mm$ if it is reinforced with 8 bars of $16mm. \theta$ as longitudinal reinforcement. Use $M20/Fe415.$
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written 7.8 years ago by
teamques10
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$$A_g=400×400=160000 mm^2$$
$A_{sc}=8-16mm ∅=8×\pi/4×16^2=1609 mm^2 \\ A_c=A_g-A_{sc}=160000-1609=158391 mm^2 \\ f_{ck}=20N/mm^2 \\ f_y=415 N/mm^2 \\ P_u=0.4 f_{ck} A_c+0.67f_y A_{sc}=0.4×20×158391+0.67×415×1609 \\ P_u=1714.51 kN$
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