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An alternation voltage is given by V= 141.4 sin 314t find i. Frequency ii. R.M.S value iii. Average value iv. Instantaneous value of voltage When t is 3 m sec
written 7.8 years ago by gravatar for teamques10 teamques10 ★ 64k modified 2.2 years ago by gravatar for prakhar1144 prakhar1144 ★ 5.0k
basic electrical engineering
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written 7.8 years ago by gravatar for teamques10 teamques10 ★ 64k •   modified 7.8 years ago

Given:

$V= 141.4 \sin 314 t \\ \text{On complaining with,} \\ V= Vm \sin 2 πft \\ We get, 2πf= 314 \\ ∴ f= 314/2π = 50 Hz \\ Vm \text{(Peak value)} = 141.4 V \\ ∴ Vrms = Vm/\vee2 = 141.4V/\vee2 = 100V \\ Vavg = 0.63 Vm = 0.63 * 1414V= 89 V \\ \text{At t= rms} \\ V(t)= 141.4 \sin (314 *3*10-3) \\ = 141.4 \sin (0.942 rod) \\ =141.4 \sin (0.942 *180) \\ =141.4 \sin (53.97) π \\ =V(t) =114.36 V$
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