User: Aditya Mekha

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Posts by Aditya Mekha

<prev • 59 results • page 1 of 6 • next >
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Answer: A: Q4A_D18$\int_c \frac{sin^6z}{(z-\frac{\pi}{6})^3}$ dz where c is the circle |z|=
... $\int_c \frac{sin^6z}{(z-\frac{\pi}{6})^3}$ dz Poles z-($\pi /6) =0$ z=$\pi/6$ and |z| =1 is a circle ,with center at origin and radius 1.The point $\pi /6 $ lies inside the circle c.Hence by cauchy formula . $\int \frac {f(z)}{(z-z_0)}=\frac {2\pi i }{(n-1)!}f^{n-1}(z_0)$ $\int \frac {sin^6z}{(z ...
written 14 hours ago by Aditya Mekha0
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Q4A_D18$\int_c \frac{sin^6z}{(z-\frac{\pi}{6})^3}$ dz where c is the circle |z|=1
... **Subject :** Applied maths 4 **Difficulty :** Medium **Marks:** 10M ...
m4e(34) written 15 hours ago by Aditya Mekha0
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Answer: A: Expand f(z) = $\frac{1}{z^2(z-1)(z+2)}$ about z=0 for i)|z|<1 ii)1<|z|<2 iii)|z|
... f(z) = $\frac{1}{z^2(z-1)(z+2)}$= $\frac {A}{z}+\frac {B}{z^2}+\frac {c}{z-1}+\frac {D}{z+2}-----(1)$ 11 1=Az(z-1)(z+2)+B(z-1)(z+2)+c(z+2)z^2+D(z-1)z^2-----(2) when z=0 in equation (2),1=0+B(-1)(2)+0+0 B=-1/2 when z=1 in eqn (2) 1=0+0+0+$c(3)(1)^2+0$ c=1/3 when z= -2 in eqn (2) 1= 0+0+0+D( ...
written 16 hours ago by Aditya Mekha0
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Expand f(z) = $\frac{1}{z^2(z-1)(z+2)}$ about z=0 for i)|z|<1 ii)1<|z|<2 iii)|z|>2
... **Subject :** Applied maths 4 **Difficulty :** Medium **Marks:** 5M ...
m4e(34) written 17 hours ago by Aditya Mekha0
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Answer: A: Calculate Rank correlation co-efficient for the following data \begin{array}{|c|
... Given $\begin{array}{|c|c|c|c|} \hline X& 10 & 12 & 18&18&15&40 \\ \hline y& 12& 18&25&25&50&25 \\ \hline \end{array}$ $\begin{array}{|c|c|} \hline sr.no& X & Rank(R1) & y&Rank(R2)&D^2 =(R1-R2)^2 \\ \hline 1& 10& 1&12&a ...
written 18 hours ago by Aditya Mekha0
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Answer: A: The Number of accidents in a year attributed to taxi driver in a city follows po
... 1)no accident in a year 2)more than 3 accidents in a year.($e^{-1}=0.3679,e^{-1} = 0.1353,e^{-2}= 0.049$ for poison distribution P(x=r) = \frac{ e^{-m}.m^{r}}{r!} where x =0,1,2 given m=3 i) no.accidents in a year, i.e.r=0 P(x=0) = $\frac {e^{-3} $\times (3)^0$ }{0!}$ P(x=0)=$\frac {0.0498\t ...
written 1 day ago by Aditya Mekha0
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