## User: Aditya Mekha

Aditya Mekha •

**0**- Reputation:
**0**- Status:
- Trusted
- Location:
- Last seen:
- 12 hours ago
- Joined:
- 4 weeks, 1 day ago
- Email:
- a*********@gmail.com

#### Academic profile

None

None

None

None

#### Posts by Aditya Mekha

<prev
• 59 results •
page 1 of 6 •
next >

0

votes

0

answers

7

views

0

answers

... **Subject :** Applied maths 4
**Difficulty :** Medium
**Marks:** 10M ...

written 14 hours ago by
Aditya Mekha •

**0**0

votes

1

answer

7

views

1

answers

... $\int_c \frac{sin^6z}{(z-\frac{\pi}{6})^3}$ dz Poles z-($\pi /6) =0$ z=$\pi/6$ and |z| =1 is a circle ,with center at origin and radius 1.The point $\pi /6 $ lies inside the circle c.Hence by cauchy formula .
$\int \frac {f(z)}{(z-z_0)}=\frac {2\pi i }{(n-1)!}f^{n-1}(z_0)$
$\int \frac {sin^6z}{(z ...

written 14 hours ago by
Aditya Mekha •

**0**0

votes

1

answer

7

views

1

answer

... **Subject :** Applied maths 4
**Difficulty :** Medium
**Marks:** 10M ...

written 15 hours ago by
Aditya Mekha •

**0**0

votes

1

answer

8

views

1

answers

... f(z) = $\frac{1}{z^2(z-1)(z+2)}$= $\frac {A}{z}+\frac {B}{z^2}+\frac {c}{z-1}+\frac {D}{z+2}-----(1)$ 11
1=Az(z-1)(z+2)+B(z-1)(z+2)+c(z+2)z^2+D(z-1)z^2-----(2)
when z=0 in equation (2),1=0+B(-1)(2)+0+0
B=-1/2
when z=1 in eqn (2)
1=0+0+0+$c(3)(1)^2+0$
c=1/3
when z= -2 in eqn (2)
1= 0+0+0+D( ...

written 16 hours ago by
Aditya Mekha •

**0**0

votes

1

answer

8

views

1

answer

... **Subject :** Applied maths 4
**Difficulty :** Medium
**Marks:** 5M ...

written 17 hours ago by
Aditya Mekha •

**0**0

votes

1

answer

8

views

1

answers

... Given $\begin{array}{|c|c|c|c|} \hline X& 10 & 12 & 18&18&15&40 \\ \hline y& 12& 18&25&25&50&25 \\ \hline \end{array}$
$\begin{array}{|c|c|} \hline sr.no& X & Rank(R1) & y&Rank(R2)&D^2 =(R1-R2)^2 \\ \hline 1& 10& 1&12&a ...

written 18 hours ago by
Aditya Mekha •

**0**0

votes

1

answer

8

views

1

answer

... **Subject :** Applied maths 4
**Difficulty :** Medium
**Marks:** 5M ...

written 18 hours ago by
Aditya Mekha •

**0**0

votes

1

answer

15

views

1

answers

... 1)no accident in a year
2)more than 3 accidents in a year.($e^{-1}=0.3679,e^{-1} = 0.1353,e^{-2}= 0.049$
for poison distribution P(x=r) = \frac{ e^{-m}.m^{r}}{r!} where x =0,1,2 given m=3
i) no.accidents in a year, i.e.r=0
P(x=0) = $\frac {e^{-3} $\times (3)^0$ }{0!}$
P(x=0)=$\frac {0.0498\t ...

written 1 day ago by
Aditya Mekha •

**0**0

votes

1

answer

15

views

1

answer

... **Subject :** Applied maths 4
**Difficulty :** Medium
**Marks:** 5M ...

written 1 day ago by
Aditya Mekha •

**0**0

votes

0

answers

7

views

0

answers

... **Subject :** Applied maths 4
**Difficulty :** Medium
**Marks:** 5M ...

written 1 day ago by
Aditya Mekha •

**0**#### Latest awards to Aditya Mekha

No awards yet. Soon to come :-)