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Fermi Energy for silver is 5-5eV. Find out energy for which the probability of occupancy at 300 K is 0.9.
written 7.8 years ago by gravatar for teamques10 teamques10 ★ 65k •   modified 7.8 years ago

Mumbai university > FE > SEM 1 > Applied Physics 1

Marks: 3M

Year: Dec 2014
engineering physics
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written 7.8 years ago by gravatar for teamques10 teamques10 ★ 65k •   modified 7.8 years ago

$$E_f = 5.5ev = 5.5 × 1.6 × 10^{-19}m = 8.8 × 10^{-19}$$ $$T = 300k$$ $$F(E) = 0.9$$

$F(E) = \frac{1}{1 + exp^{\frac{E - E_f}{KT}}}$

$ \frac{1}{F(E)} = 1 + exp^{\frac{E - E_f}{KT}}$

$ \frac{1}{8.8 × 10^{-19}} = 1 + exp^{\frac{E - E_f}{KT}}$

$Log (1.11 - 1) = log …

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