The magnetic field strength of copper is 10 ampere / metre and magnetic susceptibility is $-0.8 × 10^{-3}$ - Mumbai university > FE > SEM 1 > Applied Physics 1

Marks: 7M

Year: May 2015

Given:

$H = 10^6A/m$

$ = -0.8 ×10^{-3}$

To find: M & H = ?

Soln:

Magnetic field strength = H

Magnetic susceptibility = φ

Magnetic flux density = B

Magnetisation = M

φ = M/H

$M = φ × H = - 0.8 × 10^3$

$ B = µ_0 (M + H)$

$ = 4π ×10^{-7}(-0.8 × 10^3 + 10^6)$

$ B = 1.255 Wb/m^2$