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Mumbai university > Comp > SEM 4 > TCS
Year: Dec 2014
$$δ(q_0,(,z_0) = (q_0,(z_0)$$
$$δ(q_0,(,() = (q_0,(()$$
$$δ(q_1,),( ) =(q_1, ε)$$
$$δ(q_0, ε,z_0)=(q_f, ε)$$
What if closing bracket comes when opening bracket is on the top of the stack. That's on q0 state. You directly jumped over q1. Your diagram is correct but in equations you have no where given the q0 to q1 transition
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