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Calculate the branch current $I_1$ and $I_2$ for the circuit
1 Answer
| written 9.4 years ago by |
$\bar{Z}_1 =15+j31.4 =34.8 ⦟ 64.47°Ω \\ \bar{Z}_2 = 40-j 63.7 Ω = 75.22⦟-57.87° Ω \\ \bar{V}=200V \\ \bar{I}_1 = \dfrac{\bar{I}}{\bar{Z}_1} = \dfrac{200}{34.8 ⦟ 64.47°}=5.75⦟-64.47°A \\ \bar{I}_2 = \dfrac{\bar{I}}{\bar{Z}_2}= \dfrac{200}{75.22⦟-57.87°}=2.66⦟57.87°A$