written 9.4 years ago by
teamques10
★ 70k
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•
modified 9.4 years ago
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$P= 12 Kw \\
VL = 440 V \\
Pf= 0.7 (leading) \\
\text{For a delta connected load, Values of circuit elements} \\
VL = Vph = 440 V \\
P= \sqrt3 VLIL \cos ф \\
But, \\
P = 12 * 10-3 \\
12 * 10-3 = \sqrt3 * 440 * IL * 0.7 \\
∴ IL = 22.49 A \\
Iph= IL/\sqrt3 = 22.49/\sqrt3 = 12.98 A \\
Zph= Vpn/ Ipn = 440/12.98 = 33.89 Ω \\
Rpn = Zph \cos ф = 33.98 * 0.7 = 23.78 Ω \\
∴ 0.7 = \cos ф \\
ф = \cos -1 (0.7) \\
ф = 0.79 \\
∴ \sin ф = \sin (0.79) = 0.71 \\
Xpn = Zph \sin ф = 33.89 * 0.71 \\
= 24.06 Ω \\
\text{Reactive volt ampere}, Q= \sqrt3 VLIL \sin ф = \sqrt3 * 440 * 22.49 KVAR$