Each phase of a delta connected load consist of a 50 mH inductor in series with a parallel combination of 5 Mf capacitor. The load is connected to a three phase 55 V, 50 Hz ac supple. - 1. Phase current - 2. Light current - 3. Power drawn - 4. Power factor - 5. Reactive power and KUA - 6. Rating of the load -

Given:

$L= 50 mH \\ R= 5 Ω \\ C= 5µf \\ VL = 550 V \\ F= 50 Hz \\ \text{For a delta connected load,} \\ \text{Power factor}= XL = 2πfL = 2 * π * 50 * 50 * 10-3 = 15.707 Ω \\ XC= 1/ 2πfc = 1/ 2 * π * 50 * 5 * 10-6 = 636.61 Ω \\ Zph= jXL + R (- jXC)/ R- jXC = j15.707 + 5 (j636.61)/ 5 – j636.61 = 4.9996 + j 15.66 = 10.44 L 72.3 Ω \\ \text{Iph and IL} \\ Iph = Vph/ Zph = VL/ Zph = 550/16.44 = 33.45 A \\ IL = \sqrt3 Iph = √3 * 33.45 = 57.59 A$

Power drawn P

$P = \sqrt3 VLIL \cos ф \\ \hspace{0.3cm}=\sqrt3 * 550 * 57.95 * \cos 72.3o \\ \; \boxed{P = 16784 W}$

Power factor

$Pf = \cos 0 = \cos 72.3o = 0.304 (lag)$

Reactive power Q

$Q= \sqrt3 VLIL \sin ф \\ \hspace{0.3cm}= \sqrt3 * 550 * 57.95 * sin (72.3) \\ \; \boxed{Q = 52.591 KVAR}$

KVA rating q load

$KVA = \sqrt3VL * IL = \sqrt3* 550 * 57.95 = 95.204 KVA$