A 50 KVA, 2200/440 V, 50 Hz transformer has primary turns of 200. Determine a) flux in the core b) secondary turns c) rated primary current d) rated secondary current

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written 9.8 years ago by

teamques10 ★ 70k

• modified 6.0 years ago

basic electrical engineering

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717views

written 9.8 years ago by

teamques10 ★ 70k

Given:

KVA= 50

V1= 2200 V

V2= 440 V

f- 50 Hz

N1= 200

Flux in core

V1$= 4.44 f N1фm \\ = фm 2200/ 4.44 * 50 * 200 \\ = Фm= 004.954 Wb$

Secondary turns

N2 $= V2/V1 * N1 \\ = 490/2200 * 200 \\ = 36.36$

Rated primary current

I1 rated $= KVA * 103/ V1 \\ = 50 * 103/ 2200 \\ = 22.73 A$

Rated secondary current

I2 rated $= KVA * 103/V2 \\ = 50* 103/ 440 \\ = 113.64 A$

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