Here $\overline{F}$ = (2x - xy + z)i + (x+ y - z${}^{2}$)j+ (3x - 2y + 4z)k and S is the surface of the cylinder x${}^{2}$ + y${}^{2}$=4 bounded by the plane z = 9 and open at the other end.

$$\overline{\boldsymbol{F}}\boldsymbol{=}\left(\boldsymbol{2}\boldsymbol{x}\boldsymbol{-}\boldsymbol{y}\boldsymbol{+}\boldsymbol{z}\right)\overline{\boldsymbol{i}}\boldsymbol{+}\left(\boldsymbol{x}\boldsymbol{+}\boldsymbol{y}\boldsymbol{-}\boldsymbol{\ }{\boldsymbol{z}}^{\boldsymbol{2}}\right)\overline{\boldsymbol{j}}\boldsymbol{+(}\boldsymbol{3}\boldsymbol{x}\boldsymbol{-}\boldsymbol{2}\boldsymbol{y}\boldsymbol{+}\boldsymbol{4}\boldsymbol{z}\boldsymbol{)}\overline{\boldsymbol{k}}$$ $$\therefore\nabla \ X\ \overline{F} = \left| \begin{array}{ccc} \overline{i} & \overline{j} & \overline{k} \ \frac{\partial }{\partial x} & \frac{\partial }{\partial y} & \frac{\partial }{\partial z} \ 2x-y+z & x+y-\ z^2 & 3x-2y+4z \end{array} \right|$$ $$ = \overline{i}\ [\frac{\partial }{\partial y}(3x-2y+4z)-\ \frac{\partial }{\partial z}(2x-y+z)]-\overline{j}(\ \frac{\partial }{\partial x}(3x-2y+4z)-\ \frac{\partial }{\partial z}(2x-y+z)]$$ $$+\ \overline{k}\left[\frac{\partial }{\partial x}\left(x+y-\ z^2\right)-\frac{\partial }{\partial y}\left(2x-y+z\right)\right]=0$$ $$ = \overline{i}\ \left(-2-2z\ \right)-\overline{j}\left(3-1\right)+\overline{k}\left(1+1\right)$$ $$\ \ \ \ \ \ \ \ \ \ \ \ =\ -2\left(1+z\right)\overline{i}-2\overline{j}+2\overline{k}$$

In the plane z = 9 , Unit Normal $\overline{N}=\ \overline{K}$ and $ds=dx\ dy$

$$\therefore \overline{N}\ \left(\nabla \ X\ \overline{F}\right)=\ \overline{K}(-2\left(1+z\right)\overline{i}-2\overline{j}+2\overline{k}) = 0-0 +2 = 2$$

Now the boundary of the curved surface s and the top surface of the cylinder $S_1$ are same

So we find the surface integration of top surface,

$$\therefore \int{\int_S{\overline{N}(\nabla \ X\ \overline{F}}})\ ds=\ \int{\int_{S_1}{2dx\ dy}} \ = 2 \int\int_{S_1}dx dy\ = 2 * Area of circle S_1 \ = 2 * \Pi * 2^2 \ = 8 * \Pi$$ $$\boldsymbol{\therefore }\int{\int_{\boldsymbol{S}}{\overline{N}\boldsymbol{(}\boldsymbol{\mathrm{\nabla }}\boldsymbol{\ }\boldsymbol{X}\boldsymbol{\ }\overline{\boldsymbol{F}}}}\boldsymbol{)\ }\boldsymbol{ds}\boldsymbol{=}\boldsymbol{8}\boldsymbol{\Pi}$$