| written 9.4 years ago by | modified 3.9 years ago by |
Mumbai University > Mechanical Engineering > Sem 4 > Applied Mathematics IV
Marks: 8M
Year: May 2014
| written 9.4 years ago by | modified 3.9 years ago by |
Mumbai University > Mechanical Engineering > Sem 4 > Applied Mathematics IV
Marks: 8M
Year: May 2014
| written 9.4 years ago by |

Observed frequency:

Expected frequency:

Step 1:
Null Hypothesis $$(H_0)\ The\ performance\ in\ Mathematics\ is\ independent\ of\ performance\ in\ Physics.$$
Alternative Hypothesis : The performance in Mathematics is not independent of performance in Physics.
Step 2 :
L.O.S : 5%
Degree of freedom = (r-1)(c-1) = (3-1)*(3-1) = 4
Hence, Critical value ($X^2_{\propto }$) = 9.4877
Step 3 :

$$X^2_{cal}=\ \sum{\frac{{(O-E)}^2}{E}} = 140.3943$$
Step 4: Decision :
Since $X^2_{cal}\gt\ X^2_{\propto }$ , $H_0\ $is rejected.
Hence , the performance in Mathematics is not independent of the performance in Physics.