Mumbai University > Mechanical Engineering > Sem 4 > Applied Mathematics IV

Marks: 6M

Year: May 2015

Karl’s Pearson’s correlation co-efficient :

Let a = 36 and b = 31

n = 10 $$r_{xy}=\ r_{u,v\ }=\ \frac{n\sum{uv}-\sum{u\sum{v}}}{\sqrt{n\sum{u^2-{(\sum{u)}}^2.}}\ \sqrt{n\sum{v^2-{(\sum{v)}}^2.}}\ }$$ $$ = \frac{10\left(97\right)-0*0}{\sqrt{10\left(216\right)-0^2.\ \sqrt{10\left(162\right)-0^2}}}$$ $$ = \frac{970}{\sqrt{2160}\sqrt{1620}}$$ $$= 0.5186$$

$\boldsymbol{\mathrm{\therefore }}$ Correlation coefficient = 0.5186