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If one root of quadratic equation is $2\sqrt{3}-4$ then what is the form the quadratic equation.

written 9.3 years ago by teamques10 ★ 70k

•   modified 3.9 years ago

engineering mathematics

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written 9.1 years ago by teamques10 ★ 70k

•   modified 9.1 years ago

Given one root is $A=2√3 -4 $

So, the other root is $B=2√3 +4$

We know that, The quadratic equation is:

$(x-A)(x-B) = 0 $

$[x-(2√3 - 4)][x-(2√3 +4)] = 0$

By Simplification we get, $ x² -4√3 x -4 =0 $

So, the required quadratic equation is: $x² -4√3 x -4 =0$ `

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