Find the inverse Laplace transform of $\dfrac {s-2}{s(s+1)^3 }$

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written 9.2 years ago by

teamques10 ★ 70k

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Mumbai University > EXTC > Sem 4 > Signals and Systems

Marks : 05

Year : DEC 2014

signals and systems

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written 9.2 years ago by

teamques10 ★ 70k

By partial fraction,

$x (s)= \dfrac As +\dfrac B{(s+1)} +\dfrac C{(s+1)^2} + \dfrac D{(s+1)^3} \\ A = x (s) \times \space s \\ =\dfrac {s-2}{(s+1)^3} |s=0 = -2 \\ D = x (s) \times (s+1)^3 \\ = \dfrac{s-2}s|s=-1 = 3 \\ C = x (s) \times (s+1)^3 $

Differentiating w.r.t …

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