Find the inverse Laplace transform of the following

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written 9.2 years ago by

teamques10 ★ 70k

• modified 9.2 years ago

$(i) \space X(s)=\dfrac {s-3}{s^2+4s+13} \ (ii)\space X(s) = \dfrac {5s^2-15s-11}{(s+1)(s-2)^3}$

Mumbai University > EXTC > Sem 4 > Signals and Systems

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Year : MAY 2015

signals and systems

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written 9.2 years ago by

teamques10 ★ 70k

$$(i)\space X(s) = \dfrac {s - 3}{s^2 + 4s + 13}$$

Denominator can be written as

$X(s) = \dfrac {s - 3}{s^2 + 4s + 4 + 9 } \\ ∴X(s) = \dfrac {s - 3}{(s + 2)^2 + 9 } \\ X(s) =\dfrac { s - 3}{(s + 2)^2 …

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