| written 9.2 years ago by | • modified 9.2 years ago |
$h_1 [n]=(0.9)^n u[n]-0.5(0.9)^{n-1} u[n-1] \ h_2 [n]=(0.5)^n u[n]-(0.5)^{n-1} u[n-1]$
Mumbai University > EXTC > Sem 4 > Signals and Systems
Marks : 10
Year : MAY 2014
| written 9.2 years ago by | • modified 9.2 years ago |
$h_1 [n]=(0.9)^n u[n]-0.5(0.9)^{n-1} u[n-1] \ h_2 [n]=(0.5)^n u[n]-(0.5)^{n-1} u[n-1]$
Mumbai University > EXTC > Sem 4 > Signals and Systems
Marks : 10
Year : MAY 2014
| written 9.2 years ago by |

By using convolution property of z-transform,
$h[n]=h_1 [n]*h_2 [n](↔^z )h(z)=h_1 (z).h_2 (z) \\ ∴h_1 [n]=(0.9)^n u[n]-0.5(0.9)^{n-1} u[n-1]$
By z-transform,
$h_1 (z) = \dfrac z{z-0.9}-0.5z^{-1}\dfrac z{z-0.9} $ (shifting property)
$= \dfrac {z}{z-0.9}-\dfrac {0.5}{z-0.9} \\ =\dfrac {z-0.5}{z-0.9} \\ Now, ∴h_2 [n]=(0.5)^n u[n]-(0.5)^{n-1} u[n-1] $
By z-transform,
$h_2 (z) = \dfrac z{z-0.5}-z^{-1}\dfrac z{z-0.5}$ …