| written 9.0 years ago by | modified 3.8 years ago by |
Mumbai University > Computer Engineering > Sem 7 > Soft Computing
Marks: 5 Marks
Year: May 2016
| written 9.0 years ago by | modified 3.8 years ago by |
Mumbai University > Computer Engineering > Sem 7 > Soft Computing
Marks: 5 Marks
Year: May 2016
| written 9.0 years ago by |
Delta Training rules for bipolar continuous activation function:
The activation function in the case of bipolar continuous activation function is given by
$$f(net)=\dfrac{2}{1+exp(-net)}-1$$
We obtain
$$f' (net)=\dfrac{2exp(-net)}{[1+exp(-net)]^2}$$
An useful identify can be applied here
$$\dfrac{2exp (-net)}{[1+exp(-net)]^2} =\dfrac12 (1-0^2 )$$
Verification of identity
Letting o=f(net)
$$\dfrac12 (1-0^2 )=\dfrac12 \bigg[1-\bigg(\dfrac{1-exp(-net)}{1+exp(-net)^2}\bigg) \bigg] \\ …