Delta Training rules for bipolar continuous activation function:
The activation function in the case of bipolar continuous activation function is given by
$$f(net)=\dfrac{2}{1+exp(-net)}-1$$
We obtain
$$f' (net)=\dfrac{2exp(-net)}{[1+exp(-net)]^2}$$
An useful identify can be applied here
$$\dfrac{2exp (-net)}{[1+exp(-net)]^2} =\dfrac12 (1-0^2 )$$
Verification of identity
Letting o=f(net)
$$\dfrac12 (1-0^2 )=\dfrac12 \bigg[1-\bigg(\dfrac{1-exp(-net)}{1+exp(-net)^2}\bigg) \bigg] \\ …
Create a free account to keep reading this post.
and 3 others joined a min ago.