For the 3-bit 4x4 size image perform the following operation

1. Thresholding with T=4
2. Intensity level slicing with background r1=2 and r2=5
3. Bit plane slicing for MSB and LSB plane
4. Negation

1. Thresholding:

   Since the image is 3 bit ,L=23=8

   For thresholding

   $S=\bigg\{^{L-1 \ \ \ \ r≥T}_{0 \ \ \ \ otherwise}$

   Here,L-1=7,T=4

   7	0	0	0
   0	0	7	7
   7	0	0	0
   0	7	7	7

2. Intensity level slicing with background $r_1=2$ and $r_2=5$:

   $S=\bigg\{^{L-1 \ \ \ \ \ \ r1≤r≤r2}_{r \ \ \ \ \ \ \ otherwise}$

   Here,L-1=7,2 ≤r≤5

   7	7	7	0
   1	7	7	7
   7	7	7	1
   7	7	6	7

3. Bit plane slicing for MSB and LSB plane:

   We convert the original image into a 3-bit binary image

   100	010	011	000
   001	011	101	111
   101	011	010	001
   010	100	110	111

   We create three planes from the bit positions

   1	0	0	0
   0	0	1	1
   1	0	0	0
   0	1	1	1

   MSB plane

   0	1	1	0
   0	1	0	1
   0	1	1	0
   0	0	1	1

   0	0	1	0
   1	1	1	1
   1	1	0	1
   0	0	0	1

   LSB plane

4. Negation:

   Image neagative is given by the formula

   S=(L-1)- r

   Therefore,s=7-r

   3	5	4	7
   6	4	2	0
   2	4	5	6
   5	3	1	0