N=8

For k=5, $X(5) = x*(8-5) \\ = x*(3) = 0$

For k=6, $X(6) = x*(8-6) \\ = x*(2) = (-4-4j)$

For k=7, $X(7) = x*(8-7) \\ = x*(1) = 0$

$\therefore, X(5) = 0, X(6) = -4-4j, X(7) = 0$

**Result: X(K)={20, 0, -4+4j, 0, -4, 0, -4-4j, 0}**

(i) Let $x_1(n)=(-1)n$

$\therefore$

$\therefore, x_1$ (n)={1, -1, 1, -1, 1, -1, 1, -1}

$\therefore, X_1$(k)={0, 0, 0, 0, 8, 0, 0, 0}

By Convolution Property of DFT, Convolution of two signals in time domain is equivalent to multiplication in frequency domain.

$\therefore, P(K)= X_1(k). X(k) \ \ \ \ as, p(n) = x_1(n) * x(n)$

$\therefore$, By Convolution Theorem,

P(K) = {0, 0, 0, 0, 8, 0, 0, 0}. {20, 0, -4+4j, 0, -4, 0, -4-4j, 0}

**Result: P(K)={0, 0, 0, 0, -32, 0, 0, 0}**