Find R1 and Rf in the lossy integrator so that the peak gain is 20 dB and the gain is 3 dB down from its peak when $\omega$ = 10,000 rad/s. Use capacitance of $0.01\mu F$.

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written 9.0 years ago by

teamques10 ★ 70k

modified 3.8 years ago by

pedsangini276 • 4.8k

Mumbai University > Computer Engineering > Sem 3 > Electronic Circuits and Communication Fundamentals

Marks: 5 Marks

Year: May 2014

electronic circuits and communication

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written 9.0 years ago by

teamques10 ★ 70k

The peak value in dB is given by

$A(dB)=20 \log_{10} \dfrac{R_f}{R_1\sqrt{1+0}}=20 \\ or,\ \ \ \log_{10} \dfrac{R_f}{R_1} =1$

Thus we have, $R_f/R_1 =10 \\ Or, \ \ \ \ R_1= \dfrac{R_f}{10}$

At $ω=10^4$ rad/s, gain in dB is down by 3 dB from its peak of 20 dB, and thus …

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