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Design the sub-blocks and give the slash notation for each sub-block. Find out how many addresses are still available after these allocations.

An ISP is granted a block of addresses starting with 150.80.0.0/16. The ISP wants to distribute these blocks to 2600 customers as follows.

a. The first group has 200 medium-size businesses; each needs 128 addresses.

b. The second group has 400 small businesses; each needs 16 addresses.

c. The third group has 2000 households; each needs 4 addresses.

Design the sub-blocks and give the slash notation for each sub-block. Find out how many addresses are still available after these allocations.


Mumbai University > Computer Engineering > Sem 5 > Computer Networks

Marks: 10 Marks

Year: May 2016

a. For 128 addresses we use /25 mask. 255.255.255.128Group 1 has 200 medium size businesses150.80.0.0 /25 Subnet 1

150.80.0.128 /25 Subnet 2

150.80.1.0 /25….150.80.1.128 /25 Subnet 3

……..Subnet 100

--->150.80.99.128 /25 upto 150.80.99.255

Next address is 150.80.100.0

b. Group 2 has 400 small businesses, each needs 16 addresses…..we use /28 mask or 255.255.255.240150.80.100.0 /28 Subnet 1

150.80.100.16 /28 Subnet 2

150.80.100.240 /28 Subnet 16

…………150.80.124.240 /28 Subnet 400 [400/16=25]

Next address is 150.80.125.0

c. Group 3 has 2000 households each needs 4 addresses.For 4 addresses we use /30 mask or

255.255.255.252150.80.125.0 /30 Subnet 1

150.80.125.4 /30 Subnet 2

150.80.125.252 /30 Subnet 64

150.80.155.252 /30 Subnet 1984

31*64=1984

150.80.156.0 /30 Subnet 1985

150.80.156.60 /30 Subnet 2000

Next address available from 150.80.156.64

We have used 40000 addresses out of 65536 addresses. 25536 addresses remain available.


a. For 128 addresses we use /25 mask. 255.255.255.128Group 1 has 200 medium size businesses150.80.0.0 /25 Subnet 1

150.80.0.128 /25 Subnet 2

150.80.1.0 /25….150.80.1.128 /25 Subnet 3

……..Subnet 100

--->150.80.99.128 /25 upto 150.80.99.255

Next address is 150.80.100.0

b. Group 2 has 400 small businesses, each needs 16 addresses…..we use /28 mask or 255.255.255.240150.80.100.0 /28 Subnet 1

150.80.100.16 /28 Subnet 2

150.80.100.240 /28 Subnet 16

…………150.80.124.255 /28 Subnet 400 [400/16=25]

Next address is 150.80.125.0

c. Group 3 has 2000 households each needs 4 addresses.For 4 addresses we use /30 mask or

255.255.255.252150.80.125.0 /30 Subnet 1

150.80.125.4 /30 Subnet 2

150.80.125.252 /30 Subnet 64

150.80.155.252 /30 Subnet 1984

31*64=1984

150.80.156.0 /30 Subnet 1985

150.80.156.64/30 Subnet 2000

We have used 40000 addresses out of 65536 addresses. 25536 addresses remain available.


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