| written 9.0 years ago by | modified 3.8 years ago by |
Mumbai University > Computer Engineering > Sem 3 > Discrete Structures
Marks: 8 Marks
Year: Dec 2014
| written 9.0 years ago by | modified 3.8 years ago by |
Mumbai University > Computer Engineering > Sem 3 > Discrete Structures
Marks: 8 Marks
Year: Dec 2014
| written 9.0 years ago by |
Let A denotes numbers divisible by 2
B denotes numbers divisible by 3.
and C denotes numbers divisible by 5.
$|A| =\bigg[\dfrac{60}{2}\bigg]=30 \\ |B| =\bigg[\big[\dfrac{60}{3}\big]\bigg]=20 \\ |C| =\bigg[\big[\dfrac{60}{5}\big]\bigg]=12$
$|AՈB| =\bigg[\dfrac{60}{2 \times 3}\bigg]=10$
$|AՈC| =\bigg[\big[\dfrac{60}{2\times5}\big]\bigg]=6$
$|BՈC| =\bigg[\big[\dfrac{60}{3\times 5}\big]\bigg]=4$
$|AՈBՈC| =\bigg[\big[\dfrac{60}{2\times 3 \times 5}\big]\bigg]=2$
$|A ̅ՈB ̅ՈC ̅|=60-(30+20+12)+(10+6+4)-2=60-62+20-2=16$
This shows 16 numbers …