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Find the rank of the matrix by reducing it to normal form $\begin{vmatrix} 1&1&1\\ 1&-1&-1\\ 3&1&1\\ \end{vmatrix} $
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written 7.3 years ago by
teamques10
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Let $A=\begin{vmatrix} 1&1&1\\ 1&-1&-1\\ 3&1&1\\ \end{vmatrix} $
By $R_2-R_1$
$\begin{vmatrix} 1&1&1\\ 0&-2&-2\\ 3&1&1\\ \end{vmatrix} $
By $R_3-3R_1$
$\begin{vmatrix} 1&1&1\\ 0&-2&-2\\ 3&-2&-2\\ \end{vmatrix} $
By $R_3+R_2$
$\begin{vmatrix} 1&1&1\\ 0&-2&-2\\ 0&0&0\\ \end{vmatrix} $
There are total two non-zero rows
∴ Rank of matrix is 2.
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