Force 5KN is acting along AB where A(0,0,-1)m and B(5,-2,-4)m. Another force 8KN is acting along BC where C(3,3,4)m.

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written 8.9 years ago by

teamques10 ★ 70k

modified 3.8 years ago by

pedsangini276 • 4.8k

Find resultant of two forces and find moment of resultant force about point D(0,3,-2)m

Mumbai University > FE > Sem 1 > Engineering Mechanics

Marks : 06

Years : DEC 2015

engineering mechanics

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written 8.9 years ago by

teamques10 ★ 70k

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$F_1=5000 × \hat{AB} = \dfrac {5000 ×((5-0)i+(-2-0)j+(-4+1)k)} {\sqrt{(5-0)^2+ (-2-0)^2+(-4+1)^2}} \\ F_1 = 4055 \bar i- 1622\bar j - 2433.32 \bar k \\ F_2= 8000 × \hat{BC} = \dfrac {8000 ×((3-5)i+(3+2)j+(4+4)k)}{\sqrt{(3-5)^2+ (3+2)^2+(4+4)^2}} \\ F_2= -1659.12 \bar i + 4141.8 \bar j + 6636.5 \bar k $

Resultant,

$R=F_1+F_2=2395.88 i ̅+ 2525.8 …

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