A particle is projected from the top of a tower of height 50m with a velocity of 20m/sec at an angle 30 degrees to the horizontal. Determine:

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written 8.9 years ago by

teamques10 ★ 70k

modified 3.8 years ago by

pedsangini276 • 4.8k

(i) Horizontal distance AB it travel from the foot of the tower.

(ii) The velocity with which it strikes the ground at B.

(iii) Total time taken to reach point B.

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Mumbai University > FE > Sem 1 > Engineering Mechanics

Marks : 04

Years : DEC 2014

engineering mechanics

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written 8.9 years ago by

teamques10 ★ 70k

Given:

$U=20m/s \\ . α=30$

Let O be the origin.

Hence $0 = (0, 0)$

Hence, $B = (X,-50)$ (from the figure)

Hence, $x = ?; y = -50$

Using equation of path,

$Y= x \tan α – 4.9 x^2/ (u \cos α)^2 \\ -50 = X\tan30 – 4.9 \times …

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