12 seconds later the man sitting inside the balloon release a stone. Find the time taken by the stone to hit the ground.

$u=0 ,t=12 s ,a=0.2 m/s $ $s=ut+ \dfrac 12 at^2 \ =0+ \dfrac 12 ×0.2 ×12^2 \ =14.4 m $ ∴ stone will be released from a height of 14.4 m Initial velocity of stone = final velocity of stone after 12 sec Final velocity of stone after 12 sec, …

$$u=0 ,t=12 s ,a=0.2 m/s $$

$s=ut+ \dfrac 12 at^2 \\ =0+ \dfrac 12 ×0.2 ×12^2 \\ =14.4 m $

∴ stone will be released from a height of 14.4 m

Initial velocity of stone = final velocity of stone after 12 sec

Final velocity of stone after 12 sec, …