Mumbai University > Computer Engineering > Sem 3 > Digital Logic Design and Analysis

Marks: 2M

Year: May 2016

1. Excess-3 code

Separate digit and represent in their binary format

47.3 -> | 0100 0011 | 0111 0011 | 0011 0011 | |-----------|-----------|-----------| | 0111 | 1010 | 0110 |

Now, Excess-3 code for $(47.3)_{10}$ =$(01111010.0110)_{2}$

2. Gray Code

Binary representation for $(47.3)_{10}$ =$(101111.11)_{2}$

$(101111.11)_{2}$=$(111000.00)_{Gray Code}$

3. BCD

$(47.3)_{10}$ = $(01000111.0011)_{BCD}$