0

9.8kviews

A filament of 75 W Light bulb may be considered as black body radiating into a black enclosure of 70deg C

written 9.0 years ago by teamques10 ★ 70k

•   modified 5.7 years ago

The filament diameter is 0.1 mm and length 50 mm. considering the radiation, determine the filament temperature.

heat transfer

ADD COMMENT FOLLOW SHARE EDIT

1 Answer

0

2.1kviews

written 9.0 years ago by teamques10 ★ 70k

Q=75 W= 75 J/s

T_2=70+273=343

d=0.1 mm

L=5 cm

Area=πdl

ϵ=1 for black body

Q=σ∈A($T_1^4-T_2^4$ ) 75

=5.67×$10^(-8)×π×0.1×10^(-3)×5×10^(-2)$ ($T_1^4-343^4$)

$T_1$=3029-273=2756℃

ADD COMMENT SHARE EDIT