A cone clutch with a semi – cone angle of 150 transmits 10 kw at 600 rpm. The normal pressure intensity between the surfaces in contact is not to exceed $100kN/m^2$. The width of the friction surfaces is half to mean diameter. Assume μ=0.25. Determine

1. the outer and the inner diameter of the plate.
2. width of the cone face.
3. the axial force to engage the clutch.

Mumbai University > Mechanical Engineering > Sem 5 > Theory of Machines-II

Marks: 10 Marks

Year: Dec 2015

$α = 15˚ \\ P=10kw \\ N = 600 rpm \\ Pn = 100 KN/m^2 \\ Width l = (Mean Radius)/2 \\ = \dfrac{\dfrac{(R_1+R_2)}{2}}{2} \\ = \dfrac{R_1+R_2}{4} \\ µ = 0.25 \\ P=\dfrac{2πNT}{60}=10 \times 10^3=\dfrac{2 \times π \times 600 \times T}{60} \\ \therefore,T=159.15 N-m \\ =159.15 \times 10^3 N-mm \\ …