A two hinged parabolic arch of span 40m and rise 10m carries uniformly distributed 10 ad of 30 k/m on right half span find the reactions at the supports and draw B.M.D.

Welcome back.

and 2 others joined a min ago.

2.8kviews

written 9.1 years ago by

teamques10 ★ 70k

modified 4.1 years ago by

krithikkm200 • 10

enter image description here

Mumbai University > Civil Engineering > Sem 5 > Structural Analysis – II

Marks: 8 Marks

Year: Dec 2014

structural analysis

ADD COMMENT EDIT

1 Answer

75views

written 9.1 years ago by

teamques10 ★ 70k

ΣFy = 0 , VA + Vc = 30+20 = 600

ΣMA = 0 , 30 *20 10 = VC * 40

VC = 450 KN

VA = 150 KN

Mx = 600 X – 30 X² / 2

2 H = ∫Mx * y dx / ∫ y² dx

Y = 4 hx / L² ( L – n )

= 4 * 10 / 40² * (40 - n) = 1 * n * ( 40 - n) / 40

2 H = {∫0-40 [ 600 n – 15 n² ] * 1* (40 - n) / 40 dn ] } / { ∫0-40 [ 1*(40-n) / 40]² }

= { 15 / 40 ∫ 0-40 [ n² (40 – n )² dn ] } / { 1/40 * ∫ 0-40 [ n² ( 40 - n )² }

2 H = 600

H = 300 KN .

ADD COMMENT EDIT

Community

Content

Company