A two hinged parabolic arch of span 20 meter and rise 4 meter uniformly distributed load of 40 kN/m on right half span find the reaction at the supports and draw BMD.

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written 8.9 years ago by

teamques10 ★ 70k

modified 3.8 years ago by

pedsangini276 • 4.8k

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Mumbai University > Civil Engineering > Sem 5 > Structural Analysis – II

Marks: 8 Marks

Year: May 2015

structural analysis

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written 8.9 years ago by

teamques10 ★ 70k

ΣMA = 0

401015 – VB*20 = 0

VB = 300 KN

ΣFy = 0

VA - 40*10 + 300 = 0

VA = 100 KN

H = ∫ { ( My dx / EI ) / ( ∫ y² dx / EI ) }

Numerator = ∫ …

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