i) In a cylinder fitted with piston ii) In a Turbine

i) In a cylinder fitted with piston: for isentropic expansion

The initial volume before expansion can be found out by

$v_1=\frac{RT_1 m}{P_1}=\frac{(0.4651×(184.2+273)×1}{1000}=0.2126m^3$

$p_1 v_1^k=p_2 v_2^k$

$10×0.2126^1.327=1×v_2^k$

$v_2=1.2057m^3$

The final temperature and the boundary work are determined as

k for steam is 1.327,R=0.4651 Kj/KgK(from property table)

$T_2=\frac{P_2 V_2}{mR}=\frac{100×1.2057}{(1×0.4651)}=259.23K$

$W_b=\frac{P_2 V_2-P_1 V_1}{1-k}=\frac{100×1.2057-1000×0.2126}{1-1.327}=281.43KJ$ …